90 kelvin corresponds to approximately 1.2423 x 10-21 joules of thermal energy per particle, according to the relation E = kB × T.
This conversion comes from multiplying the temperature in kelvin by Boltzmann’s constant, which connects temperature to energy at the particle level. The kelvin scale measures absolute temperature, and joules measure energy, so this formula translates thermal energy content at the microscopic scale.
Conversion Tool
Result in joules:
Conversion Formula
The formula to convert kelvin (K) to joules (J) is:
E = kB × T
Here, E is the thermal energy in joules, kB is Boltzmann’s constant (approximately 1.380649 × 10-23 joules per kelvin), and T is the temperature in kelvin.
This works because kelvin measures absolute temperature, and Boltzmann’s constant links that temperature to the average kinetic energy of particles in a system. Multiplying the two gives the energy per particle.
Example with 90 K:
- kB = 1.380649 × 10-23 J/K
- T = 90 K
- E = 1.380649 × 10-23 × 90 = 1.2425841 × 10-21 J
Conversion Example
- Convert 50 K to joules:
- Multiply 50 by 1.380649 × 10-23 J/K
- Calculate 50 × 1.380649e-23 = 6.903245 × 10-22 J
- So, 50 K equals 6.9032 × 10-22 joules
- Convert 100 K to joules:
- Multiply 100 × 1.380649 × 10-23
- Result: 1.380649 × 10-21 J
- This means 100 kelvin corresponds to 1.3806 × 10-21 joules
- Convert 75 K to joules:
- Multiply 75 × 1.380649 × 10-23
- Result is 1.03548675 × 10-21 J
- Therefore, 75 kelvin equals about 1.0355 × 10-21 joules
Conversion Chart
| Kelvin (K) | Joules (J) |
|---|---|
| 65.0 | 8.9742 × 10-22 |
| 70.0 | 9.6645 × 10-22 |
| 75.0 | 1.0355 × 10-21 |
| 80.0 | 1.1045 × 10-21 |
| 85.0 | 1.1736 × 10-21 |
| 90.0 | 1.2426 × 10-21 |
| 95.0 | 1.3116 × 10-21 |
| 100.0 | 1.3806 × 10-21 |
| 105.0 | 1.4497 × 10-21 |
| 110.0 | 1.5187 × 10-21 |
| 115.0 | 1.5877 × 10-21 |
The chart shows the thermal energy in joules corresponding to kelvin values between 65 and 115. You can read across from a kelvin value to find the equivalent energy per particle, useful for physics calculations involving temperature and energy relations.
Related Conversion Questions
- What is the energy in joules for 90 kelvin temperature?
- How can I convert 90 K to joules using Boltzmann’s constant?
- What does 90 kelvin equal in joules in terms of thermal energy?
- Is 90 kelvin a high energy value when converted to joules?
- How many joules correspond to 90 kelvin per particle?
- Can you show the calculation of converting 90 K to joules?
- What formula do I use to get joules from kelvin at 90 degrees?
Conversion Definitions
Kelvin: Kelvin is the SI base unit of temperature, measuring absolute temperature starting from absolute zero, where particles have minimum thermal motion. It does not use degrees, and its scale increments equal to Celsius degrees. Kelvin is widely used in scientific temperature measurements.
Joules: Joule is the SI derived unit of energy, work, or heat, defined as the energy transferred when applying one newton of force over one meter distance. It quantifies all forms of energy and is fundamental to physics and engineering calculations involving power, heat, and work.
Conversion FAQs
Why does multiplying kelvin by Boltzmann’s constant give energy in joules?
Boltzmann’s constant acts as a proportionality factor between temperature measured in kelvin and the average kinetic energy of particles. Since temperature itself doesn’t measure energy directly, multiplying it by this constant translates temperature into energy units (joules) per particle.
Can I convert any temperature in kelvin directly to joules?
You can convert kelvin to joules only if interpreting the temperature as thermal energy per particle using Boltzmann’s constant. For bulk energy or macroscopic systems, additional parameters like number of particles or degrees of freedom are needed to find total energy.
Is the conversion from kelvin to joules linear or non-linear?
The basic conversion E = kB × T is linear, because joules per particle increase directly proportional with temperature in kelvin. However, in complex systems, energy relations might be non-linear depending on other factors, but the single-particle thermal energy relation is linear.
Does this conversion apply to all particles or just specific types?
The formula applies generally to the average thermal energy per particle in an ideal gas or similar systems. For particles with different properties or in different states, additional considerations are needed, but Boltzmann’s constant remains fundamental in relating temperature to energy.
How precise is the value of Boltzmann’s constant used in conversion?
The value of Boltzmann’s constant (1.380649 × 10-23 J/K) is defined exactly by the SI system since 2019, so it’s very precise. This allows accurate calculations converting kelvin to joules, without uncertainty from the constant itself.